When I was back in Melaka, my dad asked me a question. More like a brain teaser. Both my dad and I couldn't find an answer to the question. So I'm leaving it to you to work your brain and get me the answer.
The scenario
3 friends always go to this specific restaurant to have their lunch. One day, each of them ate for RM10. So they paid RM30 and left the restaurant. But the owner of the shop, knowing the 3 people are regular customers, asked the waiter in the shop to return RM5 to them. Since RM5 is hard to divide among 3 people, the waiter took RM2 and returned the remaining RM3 to each of the 3 friends.
So mathematically, each of them now ate for RM9. RM9 times by 3 (Number of people) gives you RM27. Add the RM2 that the waiter took, that leaves you with RM29. The question is, where is the RM1 gone?
Please enlighten me by leaving comments.
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6 comments:
okok...here goes. it's natural to think that the 3 people paid 9 bucks each if they get 1 buck back.
here's the solution, it's psychology. when u read that they got one buck back u forgot to count the money that the waiter took properly. the waiter took 2 hence the 3 people will pay 28 instead of 30 bucks. that's y u have to assume that the total money is 28 not 30.
so in all they're actually paying 9.33 bucks instead of 9. ok?
money out = RM30
money suppose to out = RM25
each guy paid RM 10
get back RM1 each
so each guy PAID = RM 9, total PAID = RM9 x 3 = RM 27
RM27 is more than the supposed to pay RM 25 because waiter took RM2
so money out = money suppose to out + bastard waiter
RM27 = RM 25 + RM 2
my dai jiao FYP partner want me to post this up all.....
Haha..u dai jiao la..can figure out the maths so fast..
fulamak genius la bugger...killer mathematician la...Dr Tham when you going to start teaching in Monash?Taking over keith's office ar?
look at the dai jiao
mebbe we should start calling u names like "god", "genius", "dr tham", "carol"?
HAHAHA....'CAROL'!!! That's a good one
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